Each table row shows performance measurements for this Python 3 program with a particular command-line input value N.
N | CPU secs | Elapsed secs | Memory KB | Code B | ≈ CPU Load |
---|---|---|---|---|---|
550 | 2.48 | 0.65 | 55,220 | 575 | 59% 50% 20% 38% 59% 56% 55% 55% |
Read the ↓ make, command line, and program output logs to see how this program was run.
Read spectral-norm benchmark to see what this program should do.
Python 3.3.1 (default, Apr 11 2013, 12:45:45) [GCC 4.7.2] on linux
# The Computer Language Benchmarks Game # http://benchmarksgame.alioth.debian.org/ # Contributed by Sebastien Loisel # Fixed by Isaac Gouy # Sped up by Josh Goldfoot # Dirtily sped up by Simon Descarpentries # Concurrency by Jason Stitt # 2to3 from multiprocessing import Pool from math import sqrt from sys import argv def eval_A (i, j): return 1.0 / ((i + j) * (i + j + 1) / 2 + i + 1) def eval_A_times_u (u): args = ((i,u) for i in range(len(u))) return pool.map(part_A_times_u, args) def eval_At_times_u (u): args = ((i,u) for i in range(len(u))) return pool.map(part_At_times_u, args) def eval_AtA_times_u (u): return eval_At_times_u (eval_A_times_u (u)) def part_A_times_u(xxx_todo_changeme): (i,u) = xxx_todo_changeme partial_sum = 0 for j, u_j in enumerate(u): partial_sum += eval_A (i, j) * u_j return partial_sum def part_At_times_u(xxx_todo_changeme1): (i,u) = xxx_todo_changeme1 partial_sum = 0 for j, u_j in enumerate(u): partial_sum += eval_A (j, i) * u_j return partial_sum def main(): n = int(argv[1]) u = [1] * n for dummy in range (10): v = eval_AtA_times_u (u) u = eval_AtA_times_u (v) vBv = vv = 0 for ue, ve in zip (u, v): vBv += ue * ve vv += ve * ve print("%0.9f" % (sqrt(vBv/vv))) pool = Pool(processes=4) main()
Sun, 30 Jul 2023 10:53:24 GMT COMMAND LINE: /usr/bin/python3 spectralnorm.python3-5.python3 550 PROGRAM OUTPUT: 1.274224125